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发表于 2009-6-21 22:53:57
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本帖最后由 csb 于 2009-6-21 22:55 编辑
好像就是我问的,谢啦。。。
这公式果然很那啥,rain应该能看得懂吧。。。。
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This is an extremely difficult question as it depends on a lot of factors. Assuming a somewhat simplified model of the life of a colony, the following formula is an approximation of what a colony is worth:
(-150*haz)/r +
(150*haz*(1 - r)^(-1 + (1.1111111111111112*haz)/(out*(-o + res)*ter) +
Log[100/(inf + o/30)]/Log[1 + 0.00003*out*(-o + res)] +
Log[(100000*(inf + o/30))/pop]/Log[1 + exp*(1 - haz/tol)]))/r +
(4.5*out*(1 - r)^(-1 + (1.1111111111111112*haz)/(out*(-o + res)*ter) +
Log[100/(inf + o/30)]/Log[1 + 0.00003*out*(-o + res)] +
Log[(100000*(inf + o/30))/pop]/Log[1 + exp*(1 - haz/tol)])*(-o + res))/r +
100000000*(1/70000 + (3*out)/200000)*
(1 - r)^(-1 + Log[lin/(100000*exp*(inf + o/30))]/Log[1 + exp*(1 - haz/tol)] +
Log[(100000*(inf + o/30))/pop]/Log[1 + exp*(1 - haz/tol)])*size*
((1 - r)^(-exp^(-1) + (100000000*size)/lin)/r +
((1 - r)^((-exp^(-1) + (100000000*size)/lin)/2)*
(-exp^(-1) + (100000000*size)/lin))/2) +
(83.33333333333334*haz^2*(1 - r)^(-1 + (0.5555555555555556*haz)/
(out*(-o + res)*ter) + Log[100/(inf + o/30)]/Log[1 + 0.00003*out*(-o + res)] +
Log[(100000*(inf + o/30))/pop]/Log[1 + exp*(1 - haz/tol)]))/(out*(-o + res)*ter)
Where:
pop is the initial population of the colony (typically 50),
inf is the initial infrastructure of the colony (typically 1),
o is the amount of resources you waste overharvesting,
haz is the initial climate hazard,
size is the size of the planet (1–10),
res is the resources of the planet,
tol is your hazard tolerance (starting 600),
lin is your linear growth rate (starting 50000000),
exp is your exponential growth rate (starting 3) (note: This is not the "exp" function!),
out is your industry output multiplier (starting 1, 1.15 with Waldo units),
ter is your terraforming rate (starting 0.0075),
r is your return on investment (this is 0.01 if you just accumulate savings and let them gain interest, or more if you have better things to do with the money). |
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