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[原创] 星际之剑 2 全版本通用万能存档修改器 Sots II Save Editor !!

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发表于 2011-11-4 21:37:54 | 显示全部楼层
本帖最后由 xcom333 于 2011-11-4 21:42 编辑

搞定,我把星球尺寸改成100,YD比恒星都大了.......................
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发表于 2011-11-5 01:56:40 | 显示全部楼层
我看到这个立马内蒙古牛肉拉满面了……
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发表于 2011-11-5 10:41:17 | 显示全部楼层
SQL 指令:

This one should give you 700.000.001$.
Code:
UPDATE players SET savings=700000001 WHERE id=1


This should set all the research that you can already see to finish in 1 turn.
Code:
UPDATE player_techs SET research_cost=1, feasibility=1, player_feasibility=1 WHERE player_id=1


This should set all the research that is a bit further away (not yet visible) to finish in 1 turn.
Code:
UPDATE player_tech_branches SET research_cost=1, feasibility=1 WHERE player_id=1


And this one should give you every research
Code:
UPDATE player_techs SET state=6 WHERE player_id=1
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发表于 2011-11-5 10:52:28 | 显示全部楼层
啊,sql命令.....以前学过都忘光了
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发表于 2011-11-5 12:31:43 | 显示全部楼层
yucharles  感谢啊,以后开局存档就直接命令,然后取档,方便多了!
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发表于 2011-11-5 16:04:15 | 显示全部楼层
话说,星球尺寸增大后,人口容量也增大了?
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发表于 2011-11-6 01:34:11 | 显示全部楼层
好东西收下了
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发表于 2011-11-7 08:59:25 | 显示全部楼层
SQL 指令修訂:

This one should give you 700.000.001$.
Code:
UPDATE players SET savings=700000001 WHERE id=1


This should set all the research that you can already see to finish in 1 turn.
Code:
UPDATE player_techs SET research_cost=1, feasibility=1, player_feasibility=1 WHERE player_id=1 AND feasibility>0


This should set all the research that is a bit further away (not yet visible) to finish in 1 turn.
Code:
UPDATE player_tech_branches SET research_cost=1, feasibility=1 WHERE player_id=1 AND feasibility>0


And this one should give you every research
Code:
UPDATE player_techs SET state=6 WHERE player_id=1 AND feasibility>0



Set the resources of all your colonies to 10000
Code:
UPDATE planets SET resources=10000, max_resources=10000 WHERE orbital_object_id IN (SELECT orbital_object_id FROM colonies WHERE player_id=1)



Also, set the resources in all the planets in the systems you have colonies in to 10000
Code:
UPDATE planets SET resources=10000, max_resources=10000 WHERE orbital_object_id IN (SELECT id FROM orbital_objects WHERE star_system_id IN (SELECT star_system_id FROM orbital_objects WHERE id IN (SELECT orbital_object_id FROM colonies WHERE player_id=1)))

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发表于 2011-11-8 11:48:47 | 显示全部楼层
作弊器和破解补丁的开发速度总是那么的令人惊讶~
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发表于 2011-11-10 00:03:46 | 显示全部楼层
这不是作弊器........它的存档是数据库形式保存的,用数据库工具就能打开并分析修改
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